Calculate the applied force to the piston with a 12cm radius required to elevate a weight of 2.0X104N by the piston with a 36cm radius in a hydraulic lift.

2.9 × 103 N

5.0 × 103 N

6.7 × 103 N

2.2 × 103 N

Respuesta :

Answer:

Option D is the correct answer.

Explanation:

Refer the figure given.

By Pascal's principle we have

            [tex]\frac{F_1}{A_1}=\frac{F_2}{A_2}[/tex]

F2 = 2 x 10⁴ N

[tex]A_1=\frac{\pi\times (12\times 10^{-3})^2}{4}=1.13\times 10^{-4}m^2\\\\A_2=\frac{\pi\times (36\times 10^{-3})^2}{4}=1.02\times 10^{-3}m^2[/tex]

Substituting

      [tex]\frac{F_1}{1.13\times 10^{-4}}=\frac{2\times 10^4}{1.02\times 10^{-3}}\\\\F_1=2.22\times 10^3N[/tex]

Option D is the correct answer.

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