Answer:
a) 7250.5 N
b) 4.6 m/s²
Explanation:
a)
F = applied force = 8000 N
θ = angle with the horizontal = 65 deg
Consider the motion along the vertical direction :
[tex]F_{y}[/tex] = Applied force in vertical direction in upward direction = F Sinθ = 8000 Sin65 = 7250.5 N
[tex]F_{g}[/tex] = weight of the plane in vertical direction in downward direction = ?
[tex]a_{y}[/tex] = Acceleration in vertical direction = 0 m/s²
Taking the force in upward direction as positive and in downward direction as negative, the force equation along the vertical direction can be written as
[tex]F_{y}-F_{g} = m a_{y}[/tex]
[tex]7250.5 -F_{g} = m (0)[/tex]
[tex]F_{g}[/tex] = 7250.5 N
b)
m = mass of the plane
force of gravity is given as
[tex]F_{g} = mg [/tex]
[tex]7250.5 = m(9.8) [/tex]
m = 739.85 kg
Consider the motion along the horizontal direction
[tex]F_{x}[/tex] = Applied force in horizontal direction = F Cosθ = 8000 Cos65 = 3381 N
[tex]a_{x}[/tex] = Acceleration in horizontal direction
Acceleration in horizontal direction is given as
[tex]a_{x}=\frac{F_{x}}{m}[/tex]
[tex]a_{x}=\frac{3381}{739.85}[/tex]
[tex]a_{x}[/tex] = 4.6 m/s²
