Answer: [tex]x+2y-7=0[/tex]
Step-by-step explanation:
We know that the equation of a line passing through points (a,b) and (c,d) is given by :-
[tex](y-b)=\dfrac{d-b}{c-a}(x-a)[/tex]
Then , the equation of a line passing through points (3,2) and (1,3) is given by :-
[tex](y-2)=\dfrac{3-2}{1-3}(x-3)\\\\\Rightarrow\ (y-2)=\dfrac{1}{-2}(x-3)\\\\\Rightarrow\ -2(y-2)=(x-3)\\\\\Rightarrow\ -2y+4=x-3\\\\\Rightarrow\ x+2y-7=0[/tex]
Hence, the equation of a line passing through points (3,2) and (1,3) is : [tex]x+2y-7=0[/tex]
