Answer:
3.26 x 10^9 A
Explanation:
I1 = 7.2 A, r = 18.1 cm = 0.181 m, F/l = 2.6 x 10^4 N/m
Let teh current in other wire is I2.
Use the formula of force per unit length
[tex]F / l = \frac{\mu _{0}}{4\pi }\times \frac{2 I_{1}I_{2}}{r}[/tex]
[tex]2.6 \times 10^{4} = 10^{-7}\frac{2 \times 7.2I_{2}}{0.181}[/tex]
I2 = 3.26 x 10^9 A