Answer:
[tex]\tau_{max} = 0.024 Nm[/tex]
Explanation:
Dipole moment of the electric dipole is given by the equation
[tex]P = qd[/tex]
here we have
[tex]q = 1\mu C[/tex]
d = 2 cm[/tex]
[tex]P = (1\mu C)(0.02)[/tex]
[tex]P = 2\times 10^{-8} C-m[/tex]
now the maximum torque due to electric field is given as
[tex]\tau = \vec P \times \vec E[/tex]
[tex]\tau_{max} = PE sin90[/tex]
[tex]\tau_{max} = (2\times 10^{-8})(1.2\times 10^6)[/tex]
[tex]\tau_{max} = 0.024 Nm[/tex]