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Suppose that E and F are two events and that Upper P left parenthesis Upper E and Upper F right parenthesis equals 0.1 and Upper P left parenthesis Upper E right parenthesis equals 0.2. What is Upper P left parenthesis F|E right parenthesis​

Respuesta :

Answer:

The value of [tex]P(\frac{F}{E})[/tex] is [tex]\frac{1}{2}[/tex]

Step-by-step explanation:

Given,

[tex]P(E\cap F)=0.1[/tex]

[tex]P(E)=0.2[/tex]

Thus, by the conditional probability formula,

[tex]P(\frac{F}{E})=\frac{P(E\cap F)}{P(E)}[/tex]

By substituting the values,

[tex]P(\frac{F}{E})=\frac{0.1}{0.2}[/tex]

[tex]=\frac{1}{2}[/tex]

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