Answer:
The pressure of the air is 499.91 kPa.
Explanation:
Given that,
Initial pressure = 430 kPa
Temperature = 13.0+273=286 K
Final temperature = 59.5+273=332.5 K
We need to calculate the final pressure
Using relation of pressure and temperature
At constant volume,
[tex]\dfrac{P'}{P}=\dfrac{T'}{T}[/tex]
[tex]\dfrac{P'}{430}=\dfrac{332.5}{286}[/tex]
[tex]P'=\dfrac{332.5}{286}\times430[/tex]
[tex]P'=499.91\ kPa[/tex]
Hence,The pressure of the air is 499.91 kPa.
