blueflu3367 blueflu3367

03-07-2019
Physics

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An object of weight 8N is moving along a horizontal plane. If the coefficient of kinetic friction is 0.25 find the friction force acting on the object.

Respuesta :

Vespertilio Vespertilio

06-07-2019

Answer:

2 N

Explanation:

Wight of object = mg = 8 N

Coefficient of friction, u = 0.25

The normal reaction acting on the object = N = mg = 8 N

According to the laws of limiting friction,

The friction force, f = uN

f = 0.25 x 8 = 2 N

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