Respuesta :
Explanation:
It is given that,
Mass of car A, [tex]m_A=1379\ kg[/tex]
Mass of car B, [tex]m_B=1902\ kg[/tex]
In a performance test, each of two cars takes 9.0 s to accelerate from rest to 28 m/s. Their acceleration is given by :
[tex]a=\dfrac{v-u}{t}[/tex]
[tex]a=\dfrac{28\ m/s}{9}[/tex]
a = 3.12 m/s²
(a) The net force of car A, [tex]F_A=m_Aa[/tex]
[tex]F_A=1379\ kg\times 3.12\ m/s^2[/tex]
[tex]F_A=4302.48\ N[/tex]
(b) The net force of car B, [tex]F_B=m_Ba[/tex]
[tex]F_B=1902\ kg\times 3.12\ m/s^2[/tex]
[tex]F_A=5934.24\ N[/tex]
Hence, this is the required solution.
