Answer:
Radius, r = 0.36 meters
Explanation:
It is given that,
Speed of cosmic ray electron, [tex]v=6.5\times 10^6\ m/s[/tex]
Magnetic field strength, [tex]B=10\times 10^{-5}\ T=10^{-4}\ T[/tex]
We need to find the radius of circular path the electron follows. It is given by :
[tex]qvB=\dfrac{mv^2}{r}[/tex]
[tex]r=\dfrac{mv}{qB}[/tex]
[tex]r=\dfrac{9.1\times 10^{-31}\ kg\times 6.5\times 10^6\ m/s}{1.6\times 10^{-19}\times 10^{-4}\ T}[/tex]
r = 0.36 meters
So, the radius of circular path is 0.36 meters. Hence, this is the required solution.
