Answer:
The average normal stress is 5 ksi.
Explanation:
Given that,
Diameter = 2 inch
Load = 15.71 kip
We need to calculate the average normal stress
Using formula of stress
Average normal stress [tex]\sigma =\dfrac{F}{A}[/tex]
Where, F = load
A = area
Put the value into the formula
[tex]\sigma=\dfrac{15.71}{\pi\times(\dfrac{2}{2})^2}[/tex]
[tex]\sigma = 5\ kip/inc^2[/tex]
[tex]\sigma=5\ ksi[/tex]
Hence, The average normal stress is 5 ksi.
