Answer:
k = 212.55 newton per meter
Explanation:
A girl is standing on a trampoline. Her mass is 65 kg and she is able to jump 3 meters.
We have to find the spring constant.
Since by Hooke's law,
F = -kx
Where F = force applied by the spring
k = spring constant
x = displacement
And we know force applied by the spring will be equal to the weight of the girl.
So, F = mg
Therefore, (-mg) = -kx
65×(9.81) = k×(3)
k = [tex]\frac{(65)(9.81)}{3}[/tex]
k = 212.55 N per meter
Therefore, spring constant of the spring is 212.55 Newton per meter.
