Answer:
The statue compress the stand by 3.68 x 10⁻⁵ m.
Explanation:
Change in length
[tex]\Delta L=\frac{PL}{AY}[/tex]
Load, P = 3500 x 9.81 = 34335 N
Young's modulus, Y = 2.3 x 10¹⁰ N/m²
Area, A = 7.3 x 10⁻² m²
Length, L = 1.8 m
Substituting
[tex]\Delta L=\frac{PL}{AE}=\frac{34335\times 1.8}{7.3\times 10^{-2}\times 2.3\times 10^{10}}=3.68\times 10^{-5}m[/tex]
The statue compress the stand by 3.68 x 10⁻⁵ m.
