Respuesta :
Answer:
Maximum speed = 19.81 m/s
Explanation:
Maximum speed can the car have without flying off the road at the top of the hill.
For this condition to occur we have
Centripetal force ≥ Weight of car.
[tex]\frac{mv^2}{r}\geq mg[/tex]
For maximum speed without flying we have
[tex]\frac{mv^2}{r}=mg\\\\\frac{v^2}{r}=g\\\\v=\sqrt{rg}=\sqrt{40\times 9.81}=19.81m/s[/tex]
Maximum speed = 19.81 m/s
The maximum speed of the car on top of hill is 19.8 m/s.
The given parameters;
radius of the hill, r = 40 m
The maximum speed of the car on top of hill is calculated as follows;
the centripetal force must be equal or greater than weight of the car.
[tex]F_c = mg\\\\\frac{mv^2}{r} = mg\\\\\frac{v^2}{r} = g\\\\v^2 = rg\\\\v = \sqrt{rg} \\\\v = \sqrt{40 \times 9.8} \\\\v = 19.80 \ m/s[/tex]
Thus, the maximum speed of the car on top of hill is 19.8 m/s.
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