How many iron atoms are in 0.32 mol of Fe2031? 3.9x 1023 jron atoms O 3.9 iron atoms O 6.02 x 1023 iron atoms 1.9 x 1023 iron atoms O 11x 10-24 iron atoms

Respuesta :

Answer: [tex]3.9\times 10^{23}[/tex] iron atoms

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.

[tex]1 molecule of [tex]Fe_2O_3[/tex] contains= 2 atoms of iron

[tex]1 mole of [tex]Fe_2O_3[/tex] contains=[tex]2\times 6.023\times 10^{23}=12.05\times 10^{23}[/tex]  atoms of iron

thus 0.32 moles of [tex]Fe_2O_3[/tex] contains=[tex]\frac{12.05\times 10^{23}}{1}\times 0.32=3.9\times 10^{23}[/tex]  atoms  of iron

Thus the sample would have [tex]3.9\times 10^{23}[/tex] iron atoms.