Answer:
0.2886 atm is the osmotic pressure of a solution.
Explanation:
Osmotic pressure of solution =[tex]\pi[/tex]
Concentration of the solution = c
Mass of the ammonium sulfate = 1.502 g
Moles of ammonium sulfate = [tex]\frac{1.502 g}{132.16 g/mol}=0.01136 mol[/tex]
Volume of the solution = 1 L
Concentration of the solution:
[tex]=\frac{\text{Moles of ammonium sulfate}}{\text{Volume of the solution}}[/tex]
[tex]c=\frac{0.01136 mol}{1 L}=0.01136 mol/L[/tex]
Temperature of the solution ,T= 36.54°C = 309.69 K
R = universal gas constant = 0.08206 L atm/mol K
[tex]\pi=cRT[/tex]
[tex]\pi=0.01136 mol/L\times 0.08206 L atm/mol K\times 309.69 K[/tex]
[tex]\pi=0.2886 atm[/tex]
0.2886 atm is the osmotic pressure of a solution.
