Answer:
Year in which the entrepreneur break even is 4
Step-by-step explanation:
We are given:
p(x) = x^3-4x^2+5x-20
We would find the value of x
Solving:
x^3-4x^2+5x-20 = 0
(x^3-4x^2)+(5x-20) = 0
x^2(x-4)+5(x-4) = 0
(x-4)(x^2+5)=0
=> x-4 = 0 and x^2+5 =0
x = 4 and x^2 = -5
x = 4 and x = ±√-5 or ±√5 i (not real solutions)
So, x = 4
So, year in which the entrepreneur break even is 4