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The computers of six faculty members in a certain department are to be replaced. Two of the faculty members have selected laptop machines and the other four have chosen desktop machines. Suppose that only two of the setups can be done on a particular day, and the two computers to be set up are randomly selected from the six (implying 15 equally likely outcomes; if the computers are numbered 1, 2,…, 6, then one outcome consists of computers 1 and 2, another consists of computers 1 and 3, and so on). a. What is the probability that both selected setups are for laptop computers

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Answer:

The answer is 0.067.

Step-by-step explanation:

Let the entire sample size be = s

Now there are 2 laptops in sample size, hence these can be chosen in one way only.

The required probability that both selected setups are for laptop computers can be found as:

[tex]p(two laptops)=\frac{s(two laptops)}{s}[/tex]

= [tex]\frac{1}{15}[/tex] or 0.067.

So, the probability is 0.067.

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