.
In which quadrants do solutions for the inequal
the inequality
[tex]y \leqslant \frac{2}{3}x - 4[/tex]
exist.


A.I, III, and IV
B.I, II, and III
C.I and IV
D.All four quadrants​

Respuesta :

gmany

Answer:

A.I, III, and IV

Step-by-step explanation:

The slope-intercept form of an equation of a line:

[tex]y=mx+b[/tex]

m - slope

b - y-intercept → (0, b)

If m > 0, then the function is increased

If m < 0, then the function is decreased

We have

[tex]m=\dfrac{2}{3}>0[/tex] - the function is increased

[tex]b=-4[/tex] - the y-intercept is -4 → (0, -4)

Therefore the line passes through III, IV and I quadrant.

========================================

<, ≤ - shaded region below the line

>, ≥ - shaded region above the line

========================================

We have [tex]y\leq\dfrac{2}{3}x-4[/tex] → ≤ - shaded region below the line.

Therefore the inequal the inequality exist in I, III and IV quadrant.

Look at the picture.

Ver imagen gmany

The inequality exists in quadrants A.I, III, and IV.

The answer is option A

What is a straight line graph?

  • The graph follows a straight line equation shows a straight line graph.
  • equation of a straight line is   y=mx+cy represents vertical line y-axis.
  • x represents the horizontal line x-axis.    
  • m is the slope of the line

            slope(m)=tan∅=y axis/x axis.

If m > 0, then the function is increased

If m < 0, then the function is decreased

=function is increased

=y-intercept is -4 = (0, -4)

    Therefor the line passes through III, IV and I quadrant.

  • c represents y-intercepts (it is the point at which the line cuts on the y-axis)
  • Straight line graphs show a linear relationship between the x and y values.

     

Learn more about quardinate geomtry here:-https://brainly.com/question/18269861

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