Answer:
Step-by-step explanation:
we have the system :
8x+4y=16
7y=15
the easiest unknown to find first is y because we have the second equation contains only y :
7y=15 we divide both sides by 7 we get : y=[tex]\frac{15}{7}[/tex]
then we can substitute this value in the first equation to find x :
8x+4 [tex]\frac{15}{7}[/tex] = 16
means : 8x+[tex]\frac{60}{7}[/tex] = 16
8x=16-[tex]\frac{60}{7}[/tex]
8x = [tex]\frac{52}{7}[/tex]
divide both sides by 8 :
x = [tex]\frac{13}{14}[/tex]
so the solution is ([tex]\frac{13}{14}[/tex],[tex]\frac{15}{7}[/tex])
this is the solution of the system you submitted
Now if you meant this system :
8x+4y=16
7y=15-1
we get :
7y=14 which gives us y=2
then 8x+4(2)=16 gives us : 8x+8=16
means 8x=8
means x=1
and in this case the solution will be (1,2) answer C
Answer:
x = \frac{13}{14}
Step-by-step explanation:
8x+4y=16
7y=15
the easiest unknown to find first is y because we have the second equation contains only y :
7y=15 we divide both sides by 7 we get : y=\frac{15}{7}
then we can substitute this value in the first equation to find x :
8x+4 \frac{15}{7} = 16
means : 8x+\frac{60}{7} = 16
8x=16-\frac{60}{7}
8x = \frac{52}{7}
divide both sides by 8 :
x = \frac{13}{14}
so the solution is (\frac{13}{14},\frac{15}{7})
