Answer:
4582 N
Explanation:
The initial speed of the test car is
u = 11.4 m/s
While the final speed is
v = 0
The displacement of the test car during the collision is
d = 0.78 m
So we can find the acceleration of the car by using the following SUVAT equation:
[tex]v^2 - u^2 = 2ad\\a=\frac{v^2-u^2}{2d}=\frac{0-(11.4)^2}{2(0.78)}=-83.3 m/s^2[/tex]
Now we can find the average force acting on the dummy by using Newton's second law:
F = ma
Where m = 55 kg is the mass. Substituting,
[tex]F=(55 kg)(-83.3 m/s^2)=-4582 N[/tex]
So the size of the average force is 4582 N.
