Answer:
PART A)
L = 97.4 dB
PART B)
[tex]I = 6.11 \times 10^{-6} W/m^2[/tex]
PART C)
L = 67.9 dB
Explanation:
PART A)
level of sound is given as
[tex]L = 10 Log\frac{I}{I_o}[/tex]
now we have
[tex]L = 10 Log\frac{5.50\times 10^{-3}}{10^{-12}}[/tex]
[tex]L = 97.4 dB[/tex]
PART B)
Since source is a spherical source
so here the intensity of sound is inversely depends on the square of the distance from the source
[tex]\frac{I_2}{I_1} = \frac{r_1^2}{r_2^2}[/tex]
[tex]\frac{I_2}{5.50 \times 10^-3} = \frac{1.20^2}{36^2}[/tex]
[tex]I_2 = 6.11 \times 10^{-6} W/m^2[/tex]
PART C)
level of sound is given as
[tex]L = 10 Log\frac{I}{I_o}[/tex]
now we have
[tex]L = 10 Log\frac{6.11\times 10^{-6}}{10^{-12}}[/tex]
[tex]L = 67.9 dB[/tex]