Respuesta :
The answer is 25%.
This is an example of Mendelian monohybrid cross.
If:
A - (dominant) allele for gray fur
a - (recessive) allele for orange fur
Then:
AA - dominant homozygous
Aa - heterozygous
aa - recessive homozygous
The cross between two heterozygous will be:
Parents: Aa x Aa
Offspring: AA Aa Aa aa
Thus, the offspring will be: 1 out of 4 (25%) dominant homozygous (AA), 2 out of 4 (50%) heterozygous (Aa), and 1 out of 4 (25%) recessive homozygous (aa).
Since the recessive condition results in orange fur, only recessive homozygous (aa) will have orange fur, which is 25% of all the offspring.
This is an example of Mendelian monohybrid cross.
If:
A - (dominant) allele for gray fur
a - (recessive) allele for orange fur
Then:
AA - dominant homozygous
Aa - heterozygous
aa - recessive homozygous
The cross between two heterozygous will be:
Parents: Aa x Aa
Offspring: AA Aa Aa aa
Thus, the offspring will be: 1 out of 4 (25%) dominant homozygous (AA), 2 out of 4 (50%) heterozygous (Aa), and 1 out of 4 (25%) recessive homozygous (aa).
Since the recessive condition results in orange fur, only recessive homozygous (aa) will have orange fur, which is 25% of all the offspring.
If the dominant gene in cats is the one which gives them gray fur and the recessive condition is responsible for orange fur, then two heterozygous cats which would be crossed would have offspring:
Ff (cat 1) Ff (cat 2)
FF Ff Ff ff
75% of the offspring would have gray fur (big F) and only 25% of the offspring would have orange fur (two small ffs)
Ff (cat 1) Ff (cat 2)
FF Ff Ff ff
75% of the offspring would have gray fur (big F) and only 25% of the offspring would have orange fur (two small ffs)