Respuesta :
The answer to the problem presented above is .475. Using the empirical rule, the probability that a randomly selected score lies between 500 and 700 (which is 2 standard deviations above the mean) is .475 or 47.5%.
Answer:
0.4772
Step-by-step explanation:
Mean = [tex]\mu = 500[/tex]
Standard deviation = [tex]\sigma = 100[/tex]
Now we are supposed to find the probability that a randomly selected score lies between 500 and 700.
Formula : [tex]z=\frac{x-\mu}{\sigma}[/tex]
At x = 500
[tex]z=\frac{500-500}{100}[/tex]
[tex]z=\frac{0}{100}[/tex]
At x = 700
[tex]z=\frac{700-500}{100}[/tex]
[tex]z=\frac{200}{100}[/tex]
[tex]z=2[/tex]
Now to find P(500<z<700)
P(0<z<2) =P(z<2)-P(z<0)
Now using z table :
P(z<2)-P(z<0) =0.9772-0.5000=0.4772
Thus the probability that a randomly selected score lies between 500 and 700 is 0.4772.