The peak intensity of radiation from a star named sigma is 2 x 10^6 mmkay. What is the average surface temperature of Sigma rounded to the nearest whole number?

The peak intensity of radiation from a star named sigma is 2 x 106 mmkay What is the average surface temperature of Sigma rounded to the nearest whole number class=

Respuesta :

Answer:

1.45 K

I had the same question and i got it right.

Answer:

T = 1.45 K

Explanation:

As per Wein's law we know that

[tex]\lambda = \frac{2.9 \times 10^6 nm K}{T}[/tex]

here we know that

[tex]\lambda[/tex] = wavelength of peak intensity

[tex]T [/tex] = temperature of the object

so as per above formula we know that

[tex]\lambda = 2 \times 10^6 nm[/tex]

so we have

[tex]2 \times 10^6 = \frac{2.9 \times 10^6 nm K}{T}[/tex]

[tex]T = 1.45 K[/tex]