Respuesta :

Mbrsj2000

Answer:

 

H = m c ΔT  

89.6 J = (20.0 g) × c × (40.0 - 30.0)°C  

Specific heat of iron, c = 89.6 / [20.0 × (40.0 - 30.0)] J/(g°C) = 0.448 J/(g°C)

If 89.6 joules of heat 20.0 grams of iron from 30.0 C to 40.0 C, then the specific heat of the iron in J/g. degree C is 0.448 J/g. degree C.

How do we calculate the specific heat?

The formula which we used to calculate the amount of specific heat of any substance involved in a chemical reaction is:

Q = mcΔT, where

  • Q = absorbed heat = 89.6 J
  • m = mass = 20g
  • c = specific heat = ?
  • ΔT = change in temperature = 40 - 30 = 10 degree C

On putting all these values, we get

c = 89.6 / (20)(10) = 0.448 J/g. degree C

Hence, 0.448 J/g. degree C is the specific heat of iron.

To know more about specific heat, visit the below link:

https://brainly.com/question/20350197

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