Answer:
3.34 kJ
Explanation:
FIrst of all, we need to calculate the number of moles corresponding to 10.0g of ice. This is given by
[tex]n=\frac{m }{M_m}[/tex]
where
[tex]M_m = 18.02 g/mol[/tex] is the molar mas
m = 10.0 g is the mass
Substituting
[tex]n=\frac{m}{M_m}=\frac{10 g}{18.02 g/mol}=0.555 mol[/tex]
Now we know that the heat of fusion is
[tex]H_{fus}=6.01 kJ/mol[/tex]
so the thermal energy needed to fuse the ice is
[tex]Q=n H_{fus} = (0.555 mol)(6.01 kJ/mol)=3.34 kJ[/tex]