contestada

At a pizza shop, 80% of the customers order a pizza, 15% of the customers
order a salad, and 10% of the customers order both a pizza and a salad.
If a customer is chosen at random, what is the probability that he or she
orders either a pizza or a salad?

Respuesta :

valeriarodriguoxbky9

90% out of 105% which would be 0.85

JeanaShupp

Answer: 0.85

Step-by-step explanation:

Let A be the event that the customer orders a pizza and B be the event that the customer orders a salad.

Then , we have [tex]P(A)=80\%=0.80[/tex]

[tex]P(B)=15\%=0.15[/tex]

[tex]P(A\cap B)=10\%=0.10[/tex]

Now, the probability that he or she  orders either a pizza or a salad is given by :-

[tex]P(A\cup B)=P(A)+P(B)-P(A\cap B)\\\\\Rightarrow\ P(A\cup B)=0.80+0.15-0.10=0.85[/tex]

Hence, the required probability = 0.85

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