Answer:
[tex]\boxed{x^{2} + 2x - 8}[/tex]
Step-by-step explanation:
6. Practice
The dimensions of the current park are x long and x wide.
The new park will be 4 longer and 2 thinner.
Its new dimensions will be x + 4 long and x – 2 wide.
Its new area will be
A = width × length = (x – 2)(x + 4)
Find the product
[tex]\begin{array}{lll}\textbf{Steps} & \textbf{Problem: }(x - 2)(x + 4) & \\\textbf{1. List variables} & a = x - 2 & \\ & b = x & \\ & c = 4 &\\\textbf{2. Distribute (x - 2)} & (x -2)(x + 4)\\ & = (x - 2)(x) + (x - 2)(4)\\\textbf{3. Distribute x and 4} & x^{2} -2x + 4x - 8\\\textbf{4. Combine like terms}& x^{2} + 2x - 8\\\end{array}\\\text{The area of the updated skatepark will be }\boxed{\mathbf{ x^{2} + 2x - 8}}[/tex]
