For this case we have that the figure shown is composed of three triangles and a square. By definition, the area of a triangle is given by:
[tex]A = \frac {1} {2} b * h[/tex]
Where:
b: It's the base
h: It's the height
We have 3 triangles, then the sum of their areas will be:
[tex]A = \frac {1} {2} (9 * 3.5) + \frac {1} {2} (2 * 2) + \frac {1} {2} (5 * 2)\\A = 15.75 + 2 + 5\\A = 22.75 \ units ^ 2[/tex]
On the other hand, the area of a square is given by:
[tex]A = l ^ 2[/tex]
Where:
l: It's the side of the square
According to the figure we have:
[tex]A = 2 ^ 2\\A = 4 \ units ^ 2[/tex]
So, the total area is:
[tex]A_ {t} = 22.75 + 4\\A_ {t} = 26.75 \ units ^ 2[/tex]
Answer:
[tex]A_ {t} = 26.75 \ units ^ 2[/tex]
