Respuesta :
[tex]
y-15=3x \\
-2x+5y=-3 \\ \\
-2x+y-15=0 /\cdot2 \\
-2x+5y-3=0 /\cdot(-2) \\ \\
-4x+2y-30=0 \\
4x-10y+6=0 \\ \\
-8y-24=0 \\
\boxed{y=-3} \\ \\
-3-15=3x \\
\boxed{x=-6}
[/tex]
The answer is C. (-6, -3)
Hope this helps.
r3t40
For this case we have the following system of equations:
[tex]y-15 = 3x\\-2x + 5y = -3[/tex]
We multiply the first equation by -5:
[tex]-5y + 75 = -15x[/tex]
Now we add the equations:
[tex]-2x-5y + 5y + 75 = -3-15x\\-2x + 75 = -3-15x\\-2x + 15x = -75-3\\13x = -78\\x = \frac {-78} {13}\\x = -6[/tex]
We find the value of the variable "y" according to the first equation:
[tex]y = 3x + 15\\y = 3 (-6) +15\\y = -18 + 15\\y = -3[/tex]
The solution of the system is: (-6, -3)
Answer:
(-6, -3)
Option C