Answer:
ΔG = - 2.0 kJ/mol and the reaction is spontaneous.
Explanation:
∵ ΔG = ΔH - TΔS,
ΔH = - 44.0 kJ/mol, T = 350.0 K, ΔS = - 0.12 kJ/K.mol.
∴ ΔG = ΔH - TΔS = (- 44.0 kJ/mol) - (350.0 K)(- 0.12 kJ/K.mol) = - 2.0 kJ/mol.
The sign of ΔG assigns the spontaneity of the reaction:
∵ ΔG has a negative value, so the reaction is spontaneous.
ΔG = - 2.0 kJ/mol and the reaction is spontaneous.