Respuesta :
Answer: 0.48W
useful power output=total power output*efficency
useful power output=2.4W*0.20=0.48W
useful power output=total power output*efficency
useful power output=2.4W*0.20=0.48W
The useful power output of the solar cell using the following equation will be 0.48 W. Power rating is an efficiency perameter.
What is the power rating?
The maximum power input allowed to pass through a piece of equipment is known as the equipment's power rating.
The power rating or the efficiency is found as;
[tex]\rm \eta = \frac{P_{OUT}}{P_{IN}} \\\\ P_{OUT}}= \eta \times {P_{IN} \\\\[/tex]
[tex]\rm P_{OUT}= 0.20 \times 2.4 \\\\ P_{OUT}= 0.48 \ W[/tex]
Hence, the useful power output of the solar cell will be 0.48 W
To learn more about the power rating, refer to the link;
https://brainly.com/question/13787703
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