Answer:
It will be 6400 N
Explanation:
The gravitational force between two objects is given by
[tex]F=G\frac{m_1 m_2}{r^2}[/tex]
where
G is the gravitational constant
m1, m2 are the masses of the two objects
r is the distance between the two objects
In this problem, the masses of the two objects double, so
[tex]m_1 =2 m_1\\m_2 = 2 m_2[/tex]
Substituting into the formula, we find
[tex]F'=G\frac{(2m_1)(2m_2)}{r^2}=4(G\frac{m_1 m_2}{r^2})=4F[/tex]
so, the force will quadruple, and since the original force was
F = 1600 N
The new force will be
[tex]F'=4\cdot 1600 N = 6400 N[/tex]
