A polynomial function has a root of –6 with multiplicity 1, a root of –2 with multiplicity 3, a root of 0 with multiplicity 2, and a root of 4 with multiplicity 3. If the function has a positive leading coefficient and is of odd degree, which statement about the graph is true?
A.) The graph of the function is positive on (–6, –2).
B.) The graph of the function is negative on (negative infinity symbol, 0).
C.) The graph of the function is positive on (–2, 4).
D.) The graph of the function is negative on (4, infinity symbol).

Question

Seudónimo Seudónimo

01-05-2016
Mathematics

contestada

A polynomial function has a root of –6 with multiplicity 1, a root of –2 with multiplicity 3, a root of 0 with multiplicity 2, and a root of 4 with multiplicity 3. If the function has a positive leading coefficient and is of odd degree, which statement about the graph is true?
A.) The graph of the function is positive on (–6, –2).
B.) The graph of the function is negative on (negative infinity symbol, 0).
C.) The graph of the function is positive on (–2, 4).
D.) The graph of the function is negative on (4, infinity symbol).

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Аноним Аноним · Answer 1 · 2016-05-06T02:53:10+02:00

The correct answer for the question that is being presented above is this one: "C.) The graph of the function is positive on (–2, 4)." A polynomial function has a root of –6 with multiplicity 1, a root of –2 with multiplicity 3, a root of 0 with multiplicity 2, and a root of 4 with multiplicity 3. If the function has a positive leading coefficient and is of odd degree, then C.) The graph of the function is positive on (–2, 4).

buddyhanstein buddyhanstein · Answer 2 · 2020-07-02T21:33:39+02:00

buddyhanstein buddyhanstein

02-07-2020

Answer:

C -2,4

Step-by-step explanation:

i got it right on edge

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