contestada

A positron undergoes a displacement ∆r= 2i -3j+6k, ending with the position vector r= 3j-4k, in meters. what was the positron's initial position​

Respuesta :

r3t40

[tex]

\Delta{r}=2i-3j+6k \\

r_f = 3j-4k \\

\Delta{r}=r_f-r_0\Longrightarrow2i-3j+6k=3j-4k-r_0 \\

r_0=2i-3j+6k+3j-4k=\boxed{2i+6j+10k}

[/tex]

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