Answer: 1271.7 g
Explanation: 2 Na +Cl2-------> 2 NaCl
Theoretical yield of NaCl:
500 g Nax(mole of Na/23 g of Na)X(2 mol NaCl/2 mol Na)(58.5 g NaCl/1 mol NaCl)= 1271.7 g
500 g Cl2(1 mol Cl2/35.5 g Cl2)(2 mol NaCl/1 mol Cl2)(58.5 g/1 mol NaCl)= 1647.8 g NaCl
So Na produce less amount of NaCl hence Na is limiting reagent.
So amount of NaCl=1271.7 g