Step-by-step explanation:
[tex]\begin{array}{ccc}1&-&d\\2&-&c\\3&-&a\\4&-&b\\5&-&f\\6&-&e\end{array}[/tex]
Value 1:
r = 5ft, h = 10ft. Substitute:
[tex]SA=2\pi(5)(10)+2\pi(5^2)=100\pi+50\pi=150\pi\ ft^2[/tex]
Value 2:
r = 2in, h = 4in. Substitute:
[tex]V=\dfrac{1}{3}\pi(2^2)(4)=\dfrac{1}{3}\pi(4)(4)=\dfrac{16\pi}{3}\\\\\pi\approzx3.14\to V\approx\dfrac{(16)(3.14)}{3}\approx16.75\ in^3[/tex]
Value 3:
r = 6m. Substitute:
[tex]V=\dfrac{4}{3}\pi(6^3)=\dfrac{4}{3}\pi(216)=4\pi(72)=288\pi\ m^3\\\\\pi\approx3.14\to V\approx288(3.14)=904.32\ m^3[/tex]
