Respuesta :

Answer:

She applied the exponent -2 to 4(-2) instead of applying the exponent to just -2

Step-by-step explanation:

we have the expression

[tex]\frac{4m^{-3}n^{-2}}{m^{-1} n}[/tex]

Simplify

[tex]\frac{4m^{-3}n^{-2}}{m^{-1} n}=4m^{(-3+1)}n^{(-2-1)}= 4m^{(-2)}n^{(-3)}[/tex]

Substitute the values of m and n in the expression

For[tex]m=-2, n=4[/tex]

[tex]4(-2)^{(-2)}(4)^{(-3)}=4(\frac{1}{4})* (\frac{1}{64})=\frac{1}{64}[/tex]

She applied the exponent -2 to 4(-2) instead of applying the exponent to just -2

Answer: It’s C

Step-by-step explanation:

Juss took a test