1) The graph shows a probability distribution.


What is P(X<5)?

A) 0.3

B) 0.375

C) 0.625

D) 0.7


2) The graph shows a probability distribution.


Which probabilities are equal to 0.2?


Select each correct answer.

1) P(X≤2)

2) P(X≥4)

3) P(2≤X≤4)

4) P(1≤X≤3)

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Respuesta :

1. [tex]P(X<5)[/tex] is the area under the curve to the left of [tex]x=5[/tex], which is a trapezoid with "bases" of length 2 and 5 and "height" 0.2, so

[tex]P(X<5)=\dfrac{5+2}2\cdot0.2=0.7[/tex]

2. Find the area under the curve for each of the specified intervals:

[tex]P(X\le2)=\dfrac{2\cdot0.2}2=0.2[/tex] (triangle with base 2 and height 0.2)

[tex]P(X\ge4)=\dfrac{1\cdot0.4}2=0.2[/tex] (triangle with base 1 and height 0.4)

[tex]P(2\le X\le4)=\dfrac{0.2+0.4}2\cdot2=0.6[/tex] (trapezoid with "bases" 0.2 and 0.4 and "height" 2)

[tex]P(1\le X\le3)=\dfrac{0.1+0.3}2\cdot2=0.4[/tex] (trapezoid with "bases" 0.1 and 0.3 and "height" 2)

The required probabilities are found using the  given graphs of the

probability distributions.

Response:

1) P(X< 5) is D) 0.7

2) The probability equal to 0.2 are;

  1. P(X ≤ 2)
  2. P(X ≥ 4)

How can the probabilities be calculated from the graph of a probability distribution?

The probabilities are given by the area under the curve of the graph of

the probability distribution, which are found as follows;

1) The given figure is a trapezium, which gives;

[tex]Area \ of \ a \ trapezium = \mathbf{\dfrac{a + b}{2} \cdot h}[/tex]

Where;

a, and b are the parallel sides of the trapezium

h = The height

Therefore;

[tex]P(X < 5) = \dfrac{5 + 2}{2} \times 0.2 = \mathbf{0.7}[/tex]

  • P(X< 5) = D) 0.7

2) The probabilities equal to 0.2 are found as follows;

1) At P(X ≤ 2), the area is a triangle, which gives;

[tex]Area \ of \ a \ triangle = \mathbf{\dfrac{1}{2} \times Base \ length \times Height\sqrt{x}}[/tex]

[tex]P(X \leq 2) = \dfrac{1}{2} \times 2 \times 0.2 = \mathbf{0.2}[/tex]

  • P(X ≤ 2) = 0.2

2) At P(X ≥ 4), has a triangular area, which gives;

[tex]P(X \geq 4) = \mathbf{\dfrac{1}{2} \times 1 \times 0.4}= 0.2[/tex]

  • P(X ≥ 4) = 0.2

3) P(2 ≤ X ≤4) has a trapezoidal area, which gives;

[tex]P( 2 \leq X \leq 5) = \mathbf{\dfrac{0.2 + 0.4}{2}} \times 0.2 = 0.6[/tex]

P(2 ≤ X ≤4) = 0.6 ≠ 0.2

4) P(1 ≤ X ≤ 3) has a trapezoidal area, which gives;

[tex]P( 1 \leq X \leq 3) = \dfrac{0.1 + 0.3}{2} \times 2 = 0.4[/tex]

P(1 ≤ X ≤ 3)  = 0.4 ≠ 0.2

Therefore;

The probabilities that are equal to 0.2 are;

  1. P(X ≤ 2) = 0.2
  2. P(X ≥ 4) = 0.2

Learn more about probability distributions here:

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