Answer:
0.46 J/gC
Explanation:
The specific heat capacity of a material is given by:
[tex]C_s = \frac{Q}{m \Delta T}[/tex]
where
Q is the amount of heat absorbed
m is the mass
[tex]\Delta T[/tex] is the variation of temperature
For the piece of iron in the problem:
[tex]m = 15.75 g[/tex]
[tex]Q=1086.75 J[/tex]
[tex]\Delta T=175 C-25 C=150^{\circ}[/tex]
Substituting into the equation,
[tex]C_s = \frac{1086.75 J}{(15.75 g)(150^{\circ}C)}=0.46 J/gC[/tex]
