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Kevin recorded the ages of the next 12 people who entered his grocery store. He asked his brother John to find the mean, median, and the mode of the data set: [ 6,18,8,4,18,20,10,10,21,6,17,18]. John's results are shown. mean =156/12=13. median = 20+10/2=15, mode=10. I'll post a picture of the questions. ​

Kevin recorded the ages of the next 12 people who entered his grocery store He asked his brother John to find the mean median and the mode of the data set 61884 class=

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absor201

Answer:

Step-by-step explanation:

6,18,8,4,18,20,10,10,21,6,17,18

Arrange the data in ascending order

4,6,6,8,10,10,17,18,18,18,20,21

Part A

Mean = 156/12 = 13 is correct

Median = 15 is incorrect because the data is not arranged. Median when there are even numbers will be: 10+17/2 = 13.5

Mode = 10 is incorrect, because mode is most repeating value and in the data set it is 18 so, Mode = 18

Part B

10,12 and 52 should be added in data set in ascending order

4,6,6,8,10,10,10,12,17,18,18,18,20,21,52

Mean = 230/15 = 15

Median = Middle term as odd numbers = 8th term = 12

Mode = 10 and 18

Part C

Both median and mean are used to measure central tendency.

The best measure of central tendency is considered median because the mean is affected by the presence of outliers while median is not affected by outliers.

Answer:

He is correct.

Step-by-step explanation:

I got 100% on my paper

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