Answer:
P = 76%
Step-by-step explanation:
We look for the percentage of employees who are at least 25 years old.
We know that:
μ = 32 years
[tex]\sigma = 10[/tex] years
And we want to find
[tex]P(X\geq25) [/tex]
Then we find the z-score
[tex]Z =\frac{X - \mu}{\sigma}[/tex]
So
[tex]Z = -0.7[/tex]
Then
[tex]P (X\geq25) = P(\frac{X- \mu}{\sigma}\geq\frac{25-32}{10})\\\\\P (X\geq25) = P (Z\geq -0.7)[/tex]
By symmetry of the distribution
[tex]P(Z\geq -0.7)= 1-P(Z<-0.7)[/tex]
[tex]P(Z\geq -0.7)= 1-0.242[/tex]
Looking in the normal standard tables
[tex]P(Z\geq -0.7)= 0.758[/tex]
Finally P = 76%