Individual heterozygous for both of these traits has the genotype EeFf while an individual with attached earlobes and no freckles has the genotype eeff (recessive homozygous for both traits). So:
P: EeFf x eeff
F1: (table)
A child with attached earlobes and freckles will have eeFf genotpe from these parents, and the probability is 4/16 or 1/4 (25%).