Answer:
11 students out of 902 responded above 35
Step-by-step explanation:
Using z-score we can find what percentage of student will be above 35. Using this percentage we can calculate how many students out of 902 scored above 35.
Mean = u = 26
Standard deviation = s = 4
Target Value = x = 35
Formula for the z score is:
[tex]\frac{x-u}{s}[/tex]
Using the values in this formula, we get:
[tex]\frac{35-26}{4} =2.25[/tex]
Using the z table we can find the percentage of values that would be 2.25 standard deviations above the mean in a normal distribution. Using the z-table we get this value to be 0.0122 or 1.22%
Thus 1.22% of the values will be above 35.
1.22% of 902 is 11 (rounded to nearest whole number)
Thus 11 students out of 902 responded above 35
