Answer:
The lowest of three consecutive numbers is [tex]-32[/tex]
Step-by-step explanation:
The question in English
Find the lowest of three consecutive numbers, if the sum of one-half of the lowest number plus one-third of the highest number exceeds the middle number by five.
Let
x-----> the lowest consecutive number
x+1-----> the middle consecutive number
x+2-----> the highest consecutive number
[tex]\frac{x}{2}+\frac{x+2}{3}=(x+1)+5[/tex]
solve for x
[tex]\frac{x}{2}+\frac{x+2}{3}=(x+1)+5\\ \\ \frac{3x+2x+4}{6}=x+6\\ \\5x+4=6x+36\\ \\6x-5x=4-36\\ \\x=-32[/tex]
