GIVING MANY POINTS!
Let p=x^999 − x^100+3x^9 − 5 and q=x + 1. Since q has degree 1, it follows that the remainder when p is divided by q is a constant function k, for some k. What is the value of k?

Respuesta :

The polynomial remainder theorem gives an immediate answer. It says that the remainder upon dividing [tex]p(x)[/tex] by [tex]x-c[/tex] is exactly [tex]p(c)[/tex]. In this case [tex]q=x+1\implies c=-1[/tex], and we have

[tex]k=p(-1)=(-1)^{999}-(-1)^{100}+3(-1)^9-5=-1-1-3-5=-10[/tex]

Answer:

The polynomial remainder theorem gives an immediate answer. It says that the remainder upon dividing  by  is exactly . In this case , and we have

Step-by-step explanation: