Answer:
She can chose 2 books from 8 books in 28 different way.
Step-by-step explanation:
In the given scenario the member has to chose 2 books from a group of 8 books. The order of choosing books does not matter. For example if the books are A,B,C,D,E,F,G and H, and the member picks books A and B or books B and A, she is picking up the same books. This means order of selection does not matter here, so this is a problem of combinations.
We have to form combination of 8 books taken 2 at a time i.e. 8C2
The general formula of combination is:
[tex]nCr=\frac{n!}{r!(n-r)!}[/tex]
Using the values of n=8 and r=2, we get:
[tex]8C2=\frac{8!}{2!(8-2)!}=28[/tex]
This means, she can chose 2 books from 8 books in 28 different ways.
