Answer:
Option D. [tex]42.4\ in^{3}[/tex]
Step-by-step explanation:
we know that
The volume of the cone (juice treats) is equal to
[tex]V=\frac{1}{3}\pi r^{2}h[/tex]
we have
[tex]r=3/2=1.5\ in[/tex] ----> the radius is half the diameter
[tex]h=3\ in[/tex]
assume
[tex]\pi=3.14[/tex]
substitute
[tex]V=\frac{1}{3}(3.14)(1.5)^{2}(3)=7.065\ in^{3}[/tex]
Multiply the volume of one juice treats by 6
[tex](6)7.065=42.39=42.4\ in^{3}[/tex]
