Answer:
[tex]25.0 rad/s^2[/tex]
Explanation:
First of all, we can calculate the tangential acceleration fo a point on the wheels, which is given by
[tex]a=\frac{v-u}{t}[/tex]
where
v = 30.0 m/s is the final velocity
u = 0 m/s is the initial velocity
t = 5.00 s is the time taken
Substituting,
[tex]a=\frac{30 m/s-0}{5.00 s}=6 m/s^2[/tex]
Now we can find the angular acceleration by using the following equation
[tex]\alpha=\frac{a}{r}[/tex]
where
a is the tangential acceleration
r = 24.1 cm = 0.241 m is the radius of the wheels
Substituting into the formula,
[tex]\alpha=\frac{6 m/s^2}{0.241 m}=24.9 rad/s^2 \sim 25.0 rad/s^2[/tex]
